A reversing mill hands back its flywheel energy at every pass. See how much, how fast, and why no resistor could take it.
At 7.5 reversals a minute, a resistor would have to dissipate 0.95 MW continuously, on top of the peaks. That is why reversing mills are always specified with a fully regenerative supply.
E_rev = ½ J_eq (ω₁² − ω₂²) ; P_mean = E_rev / t_r ; P_peak = J ω α