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Duty groups: why two cranes of the same capacity differ

Class of utilisation, load spectrum and the cube law of fatigue; ISO 4301 groups and CMAA classes; and what the duty group means for the motor and the drive.

25 min

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Two cranes rated for the same load can need entirely different drives, gearboxes and structures. The rated load says nothing about how often it is lifted, or how heavy the average lift is. Crane engineering therefore classifies a machine by a duty group that combines two independent measures. This lesson is course section 4.1.2.

Two measures

  • Class of utilisation: the total number of cycles the mechanism must perform in its design life. A maintenance hoist in a pumping station may make a few thousand lifts in twenty years; a ladle crane in a steelworks makes that many in a month.
  • Load spectrum (state of loading): how the loads are distributed across those cycles. A crane that lifts its rated load on nearly every cycle has a far harsher fatigue history than one whose average lift is a fifth of rated, even with the same number of cycles.

The load spectrum is summarised by the spectrum factor

kp=∑iniN(PiPmax)3(4.3)k_p = \sum_i \frac{n_i}{N}\left(\frac{P_i}{P_\text{max}}\right)^3 \tag{4.3}

where nin_i cycles are made at load PiP_i out of NN in total, and PmaxP_\text{max} is the rated load. The cube reflects the fatigue of the steel structure and the gearing: a load at half of rated does only one eighth of the damage of a full load. Light lifts fill most of the cycles but contribute almost nothing.

Try it: load spectrum and fatigue
20 %40 %60 %80 %100 %Load level P_i / P_max
  • Share of cycles
  • Share of the damage (cube law)
Spectrum factor k_p
0.11
Spectrum class
L1
Damage from the two heaviest levels
63 %

k_p = Σ (n_i / N) (P_i / P_max)³

Predict first

In the 'Light (L1)' preset, 60 % of the lifts are at 20 % of rated load. What share of the damage do they cause?

Duty groups

Combining the class of utilisation and the load spectrum gives the duty group: M1 to M8 in ISO 4301 and FEM 9.511, Class A to F in the North American CMAA specification. The spectrum itself is classed L1 (light, kp≤0.125k_p \le 0.125), L2 (≤0.25\le 0.25), L3 (≤0.5\le 0.5) and L4 (very heavy, up to 1).

GroupCMAA classTypical service
M3Bmaintenance and assembly hoists; infrequent, light average load
M5C/Dgeneral workshop and warehouse cranes; moderate regular duty
M6D/Efoundry, scrapyard and process cranes; heavy, frequent duty
M7–M8Fladle, grab and magnet cranes in continuous production; near-rated load on almost every cycle

These are design inputs, not labels: the duty group fixes the fatigue life of the structure, the service factor on the gearbox, the minimum rope safety factor and the thermal basis of the motor. It does not change the rated capacity.

What it means for the drive

  • Thermal rating. A crane motor is rated on a cyclic duration factor (CDF, Einschaltdauer): the energised share of each cycle, quoted with a cycle length, typically 40 % CDF at 10 min. This is duty type S3 to S5 from Chapter 1, not continuous S1; a drive chosen on its continuous rating alone will be undersized for a high-group crane.
  • Starts per hour. A group M7 hoist may exceed 300 starts an hour. That rules out direct-on-line switching altogether: an inverter is mandatory on thermal grounds, before any control benefit.
FoundationStart here if this is new to you

Think of two cars that can both carry 500 kg. One is a family car that carries a full load once a year; the other is a delivery van loaded to the limit forty times a day. On paper they have the same capacity; in practice the van needs stronger springs, brakes and engine cooling. A crane's duty group is the difference between the family car and the van.

ExplorerGo deeper: derivations and open questions

Design life. A mechanism is designed for a total of NN cycles. Show that a crane with kp=0.125k_p = 0.125 can make eight times as many cycles as one with kp=1k_p = 1 for the same fatigue damage. What does that say about using a light-duty crane for heavy production?

Equivalent load. The cube root kp3 Pmax\sqrt[3]{k_p}\,P_\text{max} is the constant load that would do the same damage. Compute it for the three presets. How does it compare with the arithmetic mean load?